Ariel
El rojo y los Spurs!!!
- Joined
- Sep 19, 2025
- Messages
- 310
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- 228
Yup, 14 balls and they draw 4 each time, since permutations are not considered you have 1001 combinations (14 * 13 * 12 * 11 / 4! = 1001), 1 null (draw again) and 1000 allotted to teams according to odds.Yep, I knew it was something like that. Do they put the balls back in after each round? Hard to say if landing that 3/11 would have changed the outcome of pick #2.
So they first determine #1 pick (draw 4 balls and winning combo gets the pick), then balls are returned and they determine pick #2 (if winner corresponds to a previous pick they draw again) and so on.
Anyway, this is what happened in 2025: https://www.spurstalk.com/forums/showthread.php?t=305142&p=11247429#post11247429
Bottom line, in 2025 Spurs had 60 combinations via themselves, and 7 via Atlanta. that would give them 67 combinations out of 1000 for pick #1 (6.7%). So if they landed #1, the probability of landing pick #2 would have been:Ariel said:Yeah, I ran a small program to test for the combinations given the above information and it checks out:
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So Spurs had 3 winning combinations, one of their own + 2 from Atlanta. One more small detail, I know most realize but if Spurs had gotten the first pick, that would not mean they'd have gotten no. 2 as well, a split second later by virtue of calling another team means balls are inserted at a different time and result changes. They'd have had the same chances as per the ball drawn (better if Atlanta's combinations were drawn).
Also, this means the league is running a very simple scheme where they assign contiguous combinations to the same team, this means balls are disproportionately assigned to the same teams (especially those at the top) so the lottery would be more vulnerable to being rigged. Odd that they don't shuffle the combinations to prevent this.
- If they landed #1 via one of their own combinations those are out, so chances at #2 would be: 7 / (1000 - 60) = 0.74%
- If they landed #1 via one of Atlanta's combinations those are out, so chances at #2 would be: 60 / (1000 - 7) = 6.04%
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